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• (가)$\displaystyle \frac{1} {(z+1) ^{{2}}} = \sum _ {k=1} ^ {\infty} \frac{k (-1) ^ {k+1} (z-1) ^ {k-1}} {2 ^ {k+1}}, \left | z-1 \right | <2$
• (나)$\displaystyle \frac{4} {(z-i) (z+3i)} = \sum _ {k=- \infty} ^ {-1} \left [- \frac{i ^ {k}} {3 ^ {k+1}} + (-1) ^ {k+1} i ^ {k} \right] z ^ {k}, \left | z \right | >3$
• (다)$\displaystyle \frac{1} {(z-1) (z-3)} =- \frac{1} {2 (z-1)} - \sum _ {k=0} ^ {\infty} \frac{(z-1) ^ {k}} {2 ^ {k+2}}, 0< \left | z-1 \right | <2$
• (라)$\displaystyle \frac{1} {z (1-z) ^2} = \sum _ {k=0} ^ {\infty} {\frac{k+1} {z^ {k+3}}, \left | z \right | >1}$