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• (가)$\displaystyle f (z) = \frac{2} {z^2} - \frac{5} {2z} + \sum _ {n=0} ^ {\infty} (-1) ^n \left (3- \frac{1} {2^ {2n+2}} \right) z^n, 0< \left | z \right | <1$
• (나)$\displaystyle f (z) = \sum _ {n=2} ^ {\infty} \frac{3 (-1) ^n} {z^ {n+1}} - \frac{1} {z^2} + \frac{1} {2z} - \sum _ {n=0} ^ {\infty} \frac{(-1) ^n z^n} {2^ {n+2}}, 1< \left | z \right | <2$
• (다)$\displaystyle f (z) = \sum _ {n=3} ^ {\infty} \frac{(-1) ^ {n+1} (3-2^ {n-1})} {z^n}, 2< \left | z \right | < \infty$
• (라)$\displaystyle f (z) = \frac{3} {z+1} + \sum _ {n=0} ^ {\infty} \left (2n+ \frac{7} {2} - \frac{(-1) ^ {n}} {2} \right) (z+1) ^ {n}$, $0< \left | z+1 \right | <1$