두 행렬 A = ( a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33 ) , B = ( a 11 a 12 a 13 b 21 b 22 b 23 a 31 a 32 a 33 ) A= \begin{pmatrix*}[r] a _ {11} & a _ {12} & a _ {13} \\ a _ {21} & a _ {22} & a _ {23} \\ a _ {31} & a _ {32} & a _ {33} \end{pmatrix*}, B= \begin{pmatrix*}[r] a _ {11} & a _ {12} & a _ {13} \\ b _ {21} & b _ {22} & b _ {23} \\ a _ {31} & a _ {32} & a _ {33} \end{pmatrix*} A = a 11 a 21 a 31 a 12 a 22 a 32 a 13 a 23 a 33 , B = a 11 b 21 a 31 a 12 b 22 a 32 a 13 b 23 a 33 의 행렬식이 차례대로 α , β \alpha, \beta α , β 일 때, C = ( 2 a 11 2 a 12 − 2 a 13 2 a 21 − b 21 2 a 22 − b 22 − 2 a 23 + b 23 − 2 a 31 − 2 a 32 2 a 33 ) C= \begin{pmatrix*}[r] 2a _ {11} & 2a _ {12} & -2a _ {13} \\ 2a _ {21} -b _ {21} & 2a _ {22} -b _ {22} & -2a _ {23} +b _ {23} \\ -2a _ {31} & -2a _ {32} & 2a _ {33} \end{pmatrix*} C = 2 a 11 2 a 21 − b 21 − 2 a 31 2 a 12 2 a 22 − b 22 − 2 a 32 − 2 a 13 − 2 a 23 + b 23 2 a 33 의 행렬식은? (단, α , β \alpha, \beta α , β 는 상수)
① − 8 α + 8 β -8 \alpha +8 \beta − 8 α + 8 β 내 답 ② − 8 α + 4 β -8 \alpha +4 \beta − 8 α + 4 β 내 답 ③ 8 α − 4 β 8 \alpha -4 \beta 8 α − 4 β 내 답 ④ 8 α − 8 β 8 \alpha -8 \beta 8 α − 8 β 내 답